I don’t understand what the problem is with the code, it is very simple so this is an easy one.
x = input("Give starting number: ")
y = input("Give ending number: ")
for i in range(x,y):
print(i)
It gives me an error
Traceback (most recent call last):
File "C:/Python33/harj4.py", line 6, in <module>
for i in range(x,y):
TypeError: 'str' object cannot be interpreted as an integer
As an example, if x is 3 and y is 14, I want it to print
Give starting number: 4
Give ending number: 13
4
5
6
7
8
9
10
11
12
13
What is the problem?
Mel
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asked Oct 7, 2013 at 20:56
0
A simplest fix would be:
x = input("Give starting number: ")
y = input("Give ending number: ")
x = int(x) # parse string into an integer
y = int(y) # parse string into an integer
for i in range(x,y):
print(i)
input
returns you a string (raw_input
in Python 2). int
tries to parse it into an integer. This code will throw an exception if the string doesn’t contain a valid integer string, so you’d probably want to refine it a bit using try
/except
statements.
answered Oct 7, 2013 at 20:57
BartoszKPBartoszKP
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You are getting the error because range() only takes int values as parameters.
Try using int() to convert your inputs.
answered Jun 10, 2019 at 11:20
Rahul Rahul
1612 silver badges6 bronze badges
x = int(input("Give starting number: "))
y = int(input("Give ending number: "))
for i in range(x, y):
print(i)
This outputs:
Dadep
2,7965 gold badges27 silver badges40 bronze badges
answered Sep 25, 2018 at 5:27
x = int(input("Give starting number: "))
y = int(input("Give ending number: "))
P.S. Add function int()
answered Dec 7, 2017 at 10:33
I’m guessing you’re running python3, in which input(prompt)
returns a string. Try this.
x=int(input('prompt'))
y=int(input('prompt'))
answered Oct 7, 2013 at 20:58
PerkinsPerkins
2,38924 silver badges22 bronze badges
1
You have to convert input x and y into int like below.
x=int(x)
y=int(y)
answered Dec 19, 2015 at 6:38
SPradhanSPradhan
671 silver badge8 bronze badges
You will have to put:
X = input("give starting number")
X = int(X)
Y = input("give ending number")
Y = int(Y)
BartoszKP
34.5k14 gold badges101 silver badges129 bronze badges
answered Oct 7, 2013 at 21:02
MafiaCureMafiaCure
651 gold badge1 silver badge11 bronze badges
Or you can also use eval(input('prompt'))
.
BartoszKP
34.5k14 gold badges101 silver badges129 bronze badges
answered Feb 6, 2017 at 6:57
3
I am writing a code where the program draws the amount of cards that was determined by the user. This is my code:
from random import randrange
class Card:
def __init__(self, rank, suit):
self.rank = rank
self.suit = suit
self.ranks = [None, "ace", "2", "3", "4", "5", "6", "7", "8",
"9", "10", "jack", "queen", "king"]
self.suits = {"s": "spades","d": "diamonds","c": "clubs","h": "hearts"}
def getRank(self):
return self.rank
def getSuit(self):
return self.suit
def __str__(self):
return "%s of %s" % (self.ranks[self.rank], self.suits.get(self.suit))
def draw():
n = input("Enter the number of cards to draw: ")
for i in range(n):
a = randrange(1,13)
b = randrange(1,4)
c=Card(a,b)
print (c)
draw()
And this is the error I keep getting:
Traceback (most recent call last):
File "main.py", line 31, in <module>
draw()
File "main.py", line 24, in draw
for i in range(n):
TypeError: 'str' object cannot be interpreted as an integer
Any help would be appreciated.
If you are getting trouble with the error “TypeError: ‘str’ object cannot be interpreted as an integer”, do not worry. Today, our article will give a few solutions and detailed explanations to handle the problem. Keep on reading to get your answer.
Why does the error “TypeError: ‘str’ object cannot be interpreted as an integer” occur?
TypeError is an exception when you apply a wrong function or operation to the type of objects. “TypeError: ‘str’ object cannot be interpreted as an integer” occurs when you try to pass a string as the parameter instead of an integer. Look at the simple example below that causes the error.
Code:
myStr = "Welcome to Learn Share IT" for i in range(myStr): print(i)
Result:
Traceback (most recent call last)
in <module>
----> 3 for i in range(myStr):
TypeError: 'str' object cannot be interpreted as an integer
The error occurs because the range()
function needs to pass an integer number instead of a string.
Let’s move on. We will discover solutions to this problem.
Solutions to the problem
Traverse a string as an array
A string is similar to an array of strings. As a result, when you want to traverse a string, do the same to an array. We will use a loop from zero to the length of the string and return a character at each loop. The example below will display how to do it.
Code:
myStr = "Welcome to Learn Share IT" for i in range(len(myStr)): print(myStr[i], end=' ')
Result:
W e l c o m e t o L e a r n S h a r e I T
Traverse elements
The range()
function is used to loop an interval with a fix-step. If your purpose is traversing a string, loop the string directly without the range()
function. If you do not know how to iterate over all characters of a string, look at our following example carefully.
Code:
myStr = "Welcome to Learn Share IT" for i in myStr: print(i, end=' ')
Result:
W e l c o m e t o L e a r n S h a r e I T
Use enumerate() function
Another way to traverse a string is by using the enumerate()
function. This function not only accesses elements of the object but also enables counting the iteration. The function returns two values: The counter and the value at the counter position.
Code:
myStr = "Welcome to Learn Share IT" for counter, value in enumerate(myStr): print(value, end=' ')
Result:
W e l c o m e t o L e a r n S h a r e I T
You can also get the counter with the value like that:
myStr = "Welcome to Learn Share IT" for counter, value in enumerate(myStr): print(f"({counter},{value})", end= ' ')
Result:
(0,W) (1,e) (2,l) (3,c) (4,o) (5,m) (6,e) (7, ) (8,t) (9,o) (10, ) (11,L) (12,e) (13,a) (14,r) (15,n) (16, ) (17,S) (18,h) (19,a) (20,r) (21,e) (22, ) (23,I) (24,T)
Summary
Our article has explained the error “TypeError: ‘str’ object cannot be interpreted as an integer” and showed you how to fix it. We hope that our article is helpful to you. Thanks for reading!
Maybe you are interested:
- UnicodeDecodeError: ‘ascii’ codec can’t decode byte
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My name is Robert Collier. I graduated in IT at HUST university. My interest is learning programming languages; my strengths are Python, C, C++, and Machine Learning/Deep Learning/NLP. I will share all the knowledge I have through my articles. Hope you like them.
Name of the university: HUST
Major: IT
Programming Languages: Python, C, C++, Machine Learning/Deep Learning/NLP
Python range() function can only accept integer values as arguments. If we try to pass a string number value as an argument, we receive the error
»
TypeError: 'str' object cannot be interpreted as an integer
»
.
If you encounter the same error while executing a Python program and don’t know why it occurs and how to resolve it, this article is for you.
This Python tutorial discusses »
TypeError: 'str' object cannot be interpreted as an integer
» in detail. It helps you understand this error with a typical example of where you may encounter it in your program.
Python range() Function
Python provides a function called range() that returns a sequence of numbers, starting from 0 by default, in a given range. It accepts three parameters — start, stop, and step.
-
Start
— The start value of a sequence. -
Stop
— The next value after the end value of a sequence. -
Step
— It is an integer value denoting the difference between two consecutive numbers in a sequence.
This method is primarily used with
Python for loop
. Here is an example of how the range() function works:
even_numbers = range(0, 10, 2)
for n in even_numbers:
print(n)
Output
0
2
4
6
8
When you use a string value in the range() function, you get the error
TypeError: 'str' object cannot be interpreted as an integer
.
If the range() method accepts a string value, it will be quite confusing for the Python interpreter to determine what range of numbers should be displayed. Hence, passing integer values as arguments to the range() function is necessary.
Error Example
even_numbers = range(0, '10', 2)
for n in even_numbers:
print(n)
Output
Traceback (most recent call last):
File "/home/main.py", line 1, in <module>
even_numbers = range(0, '10', 2)
TypeError: 'str' object cannot be interpreted as an integer
In this example, we received the error because the second argument in the
range(0,
'10'
, 2)
function is a string.
By reading the error statement,
TypeError: 'str' object cannot be interpreted as an integer
, we can conclude why Python raised this error.
Like a standard error statement, this error also has two sub-statements.
-
TypeError
— The exception type -
The ‘str’ object cannot be interpreted as an integer
— The error message
We receive the TypeError exception becaue the range function excepts the value of the
int
data type, and we passed a string. And the error message ‘
str' object cannot be interpreted as an integer
clearly tells us that the Python interpreter can not use the value of the string data type, as it only accepts an integer.
Example
Let’s discuss a common case where you may encounter the above error in your Python program.
Let’s say we need to write a program that prints all the prime numbers between 1 to n, where n is the last number of the series.
Program
#function that check if the number is a prime number or not
def is_prime(num):
for i in range(2,num):
if num % i ==0:
return False
return True
#input the number upto which we want to find the prime numbers
n = input("Enter the last number: ")
print(f"Prime numbers upto {n} are:")
for i in range(2,n):
if is_prime(i):
print(i)
Output
Enter the last number: 12
Prime numbers upto 12 are:
Traceback (most recent call last):
File "main.py", line 12, in
for i in range(2,n):
TypeError: 'str' object cannot be interpreted as an integer
Break the Code
The above error indicates that there is something wrong with the statement
for i in range(2,n)
. The error message states that the value
n
is not an integer. Hence, throws the TypeError exception.
Solution
Whenever we accept input from the user, it is always stored in string data type. If we want to pass that input data into a function like
range()
, we first need to convert it into an integer using the
int()
function.
#function that check if the number is a prime number or not
def is_prime(num):
for i in range(2,num):
if num % i ==0:
return False
return True
#input the number upto which we want to find the prime numbers
#and convert it into integer
n = int(input("Enter the last number: "))
print(f"Prime numbers upto {n} are:")
for i in range(2,n+1):
if is_prime(i):
print(i)
Output
Enter the last number: 12
Prime numbers upto 12 are:
2
3
5
7
11
Now, our code runs smoothly without any errors, and we get the desired output.
Conclusion
The Error
TypeError: 'str' object cannot be interpreted as an integer
is very common when we deal with the Python range() function. This error occurs when we pass a string value to the range() function instead of integers. The most common case is when we input the data from the user and use the same data with the range function without converting it into an integer.
If you still get this error in your Python program, please send your query and code in the comment section. We will try to help you as soon as possible
.
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Learn how to fix the common Python error, «TypeError: ‘str’ object cannot be interpreted as an integer», with this step-by-step guide. We’ll help you understand the root cause of this error and provide solutions to resolve it.
Table of Contents
- Understanding the Error
- Common Causes and Solutions
- Using int() Function
- Using List Comprehension
- Using map() Function
- FAQs
Understanding the Error
The «TypeError: ‘str’ object cannot be interpreted as an integer» error occurs when you try to use a string value in a context where Python expects an integer value. This is a common mistake, especially for beginners who might not be aware of the differences between data types in Python.
To fix this error, you need to convert the string to an integer using built-in functions or other techniques, as we’ll discuss in the next section.
Common Causes and Solutions
Here are some common causes of the «TypeError: ‘str’ object cannot be interpreted as an integer» error and their solutions:
Using int() Function
One of the most common causes of this error is using a string value as an index. For example:
my_list = [1, 2, 3, 4, 5]
index = "2"
print(my_list[index])
This code will throw the error because the index
variable is a string. To fix this, you can use the int()
function to convert the string to an integer:
my_list = [1, 2, 3, 4, 5]
index = "2"
print(my_list[int(index)])
Now the code will run without any errors.
Using List Comprehension
Another common cause of this error is trying to perform arithmetic operations with a list of strings. For example:
list_of_strings = ["1", "2", "3", "4", "5"]
sum_of_list = sum(list_of_strings)
To fix this, you can use list comprehension to convert the list of strings to a list of integers:
list_of_strings = ["1", "2", "3", "4", "5"]
list_of_integers = [int(x) for x in list_of_strings]
sum_of_list = sum(list_of_integers)
Now the code will run without any errors.
Using map() Function
Another way to convert a list of strings to a list of integers is to use the map()
function, which applies a function to all items in a list:
list_of_strings = ["1", "2", "3", "4", "5"]
list_of_integers = list(map(int, list_of_strings))
sum_of_list = sum(list_of_integers)
Now the code will run without any errors.
FAQs
Q1: Can I use float() instead of int() to convert strings to numbers?
Yes, you can use the float()
function to convert a string to a floating-point number. However, if you need an integer value, you should use the int()
function instead.
Q2: How do I handle cases where the string cannot be converted to an integer?
You can use a try
—except
block to handle cases where the string cannot be converted to an integer. For example:
try:
result = int("some_string")
except ValueError:
print("The string cannot be converted to an integer.")
Q3: Can I use the int()
function to convert a list of strings to a list of integers directly?
No, you cannot use the int()
function directly on a list of strings. Instead, you should use list comprehension or the map()
function, as shown in the Common Causes and Solutions section.
Q4: What if I want to convert a string with decimal values to an integer?
You can first use the float()
function to convert the string to a floating-point number, and then use the int()
function to convert the floating-point number to an integer. However, keep in mind that this will truncate the decimal part of the number.
string_with_decimal = "3.14"
integer_value = int(float(string_with_decimal))
Q5: Can I use the int()
function to convert a string with leading or trailing whitespaces to an integer?
Yes, the int()
function can handle strings with leading or trailing whitespaces:
string_with_whitespaces = " 42 "
integer_value = int(string_with_whitespaces)
However, if the string contains any other non-numeric characters, you’ll need to remove them before using the int()
function.
- Python int() Function
- Python float() Function
- Python map() Function