Php как вывести ошибку sql

Note. There is a bug in either documentation about error_reporting() or in mysql_error() function cause manual for mysql_error(), says:  "Errors coming back from the MySQL database backend no longer issue warnings." Which is not true.

Just spent a good 30 minutes trying to figure out why i didn't see my SQL errors.

<?php

function escape_data($data){

global $dbc;

if(ini_get('magic_quotes_gpc')){

  $data=stripslashes($data);

}

return mysql_real_escape_string(trim($data),$dbc);

}

function

q($page,$query){

// $page

$result = mysql_query($query);

if (mysql_errno()) {

  $error = "MySQL error ".mysql_errno().": ".mysql_error()."n<br>When executing:<br>n$queryn<br>";

  $log = mysql_query("INSERT INTO db_errors (error_page,error_text) VALUES ('$page','".escape_data($error)."')");

}

}
// Run the query using q()

$query = "INSERT INTO names (first, last) VALUES ('myfirst', 'mylast'");

$result = q("Sample Page Title",$query);

?>

This example prompts an error in debugmode (variable $b_debugmode ). An e-mail with the error will be sent to the site operator otherwise.

The script writes a log file in directory ( in this case /log ) as well.

The system is vulnerable when database/query information is prompted to visitors. So be sure to hide this information for visitors anytime.

Regars,

Lennart Poot
http://www.twing.nl

<?php
$b_debugmode = 1; // 0 || 1$system_operator_mail = 'developer@company.com';
$system_from_mail = 'info@mywebsite.com';

function

db_query( $query ){
  global $b_debugmode;// Perform Query
  $result = mysql_query($query);// Check result
  // This shows the actual query sent to MySQL, and the error. Useful for debugging.
  if (!$result) {
    if($b_debugmode){
      $message  = '<b>Invalid query:</b><br>' . mysql_error() . '<br><br>';
      $message .= '<b>Whole query:</b><br>' . $query . '<br><br>';
      die($message);
    }raise_error('db_query_error: ' . $message);
  }
  return $result;
}

  function

raise_error( $message ){
    global $system_operator_mail, $system_from_mail;$serror=
    "Env:       " . $_SERVER['SERVER_NAME'] . "rn" .
    "timestamp: " . Date('m/d/Y H:i:s') . "rn" .
    "script:    " . $_SERVER['PHP_SELF'] . "rn" .
    "error:     " . $message ."rnrn";// open a log file and write error
    $fhandle = fopen( '/logs/errors'.date('Ymd').'.txt', 'a' );
    if($fhandle){
      fwrite( $fhandle, $serror );
      fclose(( $fhandle ));
     }// e-mail error to system operator
    if(!$b_debugmode)
      mail($system_operator_mail, 'error: '.$message, $serror, 'From: ' . $system_from_mail );
  }?>

$result = mysql_query($query) or die("<b>A fatal MySQL error occured</b>.n<br />Query: " . $query . "<br />nError: (" . mysql_errno() . ") " . mysql_error());

This will print out something like...

A fatal MySQL error occured.

Query: SELECT * FROM table

Error: (err_no) Bla bla bla, you did everything wrong

It's very useful to see your query in order to detect problems with syntax. Most often, the output message from MySQL doesn't let you see enough of the query in the error message to let you see where your query went bad- it a missing quote, comma, or ( or ) could have occured well before the error was detected. I do -not- recomend using this procedure, however, for queries which execute on your site that are not user-specific as it has the potential to leak sensative data. Recomended use is just for debugging/building a script, and for general user-specific queries which would at the worst, leak the users own information to themself.

Good luck,

-Scott

Would it make sense to change the examples in the documentation for mysql_query () and for mysql_error () accordingly?

ERROR 1044: Access denied for user: 'ituser@mail.ramon.intranet' to database 'itcom'

This error ocurrs when a intent of a sql insert of no authorized user. The results: mysql_errno = 0 and the mysql_error = "" .

Warning: mysql_connect() [function.mysql-connect]: Unknown MySQL server host 'locallllllhost' (11001)

That's a warning, which is not trapped by mysql_error()!

$result = mysql_query($query) or die("<b>A fatal MySQL error occured</b>.n<br />Query: " . $query . "<br />nError: (" . mysql_errno() . ") " . mysql_error());

This will print out something like...

<b>A fatal MySQL error occured</b>.
Query: SELECT * FROM table
Error: (err_no) Bla bla bla, you did everything wrong

It's very useful to see your query in order to detect problems with syntax. Most often, the output message from MySQL doesn't let you see enough of the query in the error message to let you see where your query went bad- it a missing quote, comma, or ( or ) could have occured well before the error was detected. I do -not- recomend using this procedure, however, for queries which execute on your site that are not user-specific as it has the potential to leak sensative data. Recomended use is just for debugging/building a script, and for general user-specific queries which would at the worst, leak the users own information to themself.

Good luck,

-Scott

    function myquery ($query) {
        $result = mysql_query($query);
        if (mysql_errno())
            echo "MySQL error ".mysql_errno().": ".mysql_error()."n<br>When executing:<br>n$queryn<br>";
        return $result;
    }

MYSQL: Client does not support authentication protocol requested by server; consider upgrading MySQL client

According to the MySQL site (http://dev.mysql.com/doc/refman/5.0/en/old-client.html) the best fix for this is to use the OLD_PASSWORD() function for your mysql DB user. You can reset it by issuing to MySQL:

Set PASSWORD for 'user'@'host' = OLD_PASSWORD('password');

This saved my hide.

<?php
$old_track = ini_set('track_errors', '1');

.....

        if (

$this->db_handle!=FALSE && $db_selection_status!=FALSE)
            {
            $this->connected=1;
            ini_set('track_errors', $old_track);
            }
        else
            {
            $this->connected=-1;
            $mysql_warning=$php_errormsg;
            ini_set('track_errors', $old_track);
            throw new mysql_cns_exception(1, $mysql_warning . " " . mysql_error());
            }
?>

   $ conn = mysql_connect ('localhost', 'root', '');
   $ conn2 = mysql_connect ('localhost', 'root', '');

     mysql_select_db ('db1', $ conn);
   mysql_select_db ('db2', $ conn2);

     $ result = mysql_query ("select 1 from dual", $ conn);
   $ result2 = mysql_query ("select 1 from luad", $ conn2);

     echo mysql_error ($ conn) "<hr>".
   echo mysql_error ($ conn2) "<hr>".

The reason for this is that mysql_connect not working as expected a further connection returns. Since the parameters are equal, a further reference to the previous link is returned. So also changes the second mysql_select_db the selected DB of $conn to 'db2'.

If you change the connection parameters of the second connection to 127.0.0.1, a new connection is returned. In addition to the parameters new_link the mysql_connect() function to be forced.