Ошибка в питоне bad input - ErrorsMaster.ru - большая энциклопедия ошибок и их решений

I have this code:

num = range(1,33)
num[0]=1
num[1]=2
for i in range(2,32):
    num[i]=num[i-1]+num[i-2]


total=0
for i in range(0,32):
    print num[i]
    if num[i]%2==0:
    total=total+num[i]
    else:
    num[i]=num[i+1]

I want to find the sum of the even numbers in the num array. Can anyone suggest what I did wrong here ?

Tomerikoo

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asked Apr 15, 2013 at 19:32

Indentation is very important in python

if num[i]%2==0:
total=total+num[i]
else:
num[i]=num[i+1]

should be

if num[i]%2==0:
    total=total+num[i]
else:
    num[i]=num[i+1]

Also, use consistent indentation e.g 4 spaces every where you have to introduce indentation.

answered Apr 15, 2013 at 19:33

karthikrkarthikr

96.9k26 gold badges196 silver badges188 bronze badges

Alternatively:

total = sum([i for i in num if i % 2 == 0])

Sum( ) will return the summation of a list.
[i for i in num if i % 2 == 0] is a List Comprehensions.

For example:

>> num = [1,2,3,4]
>> tmp = [i for i in num if i % 2 == 0]
>> print tmp
[2,4]

>> total = sum(tmp)
>> print total
6

answered Apr 15, 2013 at 19:37

Источник

0 / 0 / 0

Регистрация: 25.12.2018

Сообщений: 10

28.12.2018, 21:17. Показов 14471. Ответов 5

Помогите разобраться с ошибками
Пример:
a = int(input())
b = int(input())
c = int(input())

print (‘maximum’,end=»»)

if b <= a >= c:
print (a)
elif a <= b >= c:
print (b)
elif a <= c >= b:
print(c)

SyntaxError: bad input on line 5

swillrocker

337 / 126 / 114

Регистрация: 09.04.2011

Сообщений: 246

28.12.2018, 21:36

У меня вроде работает все…

Python

a = int(input())
b = int(input())
c = int(input())
 
print ('maximum',end=" ")
 
if b <= a >= c:
    print (a)
elif a <= b >= c:
    print (b)
elif a <= c >= b:
    print(c)

Кликните здесь для просмотра всего текста

1
2
3
maximum3
>>>
================= RESTART: C:/Users/Quasar/Desktop/py/123.py =================
6
2
1
maximum6
>>>
================= RESTART: C:/Users/Quasar/Desktop/py/123.py =================
6
6
6
maximum6
>>>
================= RESTART: C:/Users/Quasar/Desktop/py/123.py =================
6
6
6
maximum 6
>>>

0 / 0 / 0

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Сообщений: 10

28.12.2018, 21:40

[ТС]

Тогда я понял, это в интернете компилятор онлайн какой то глючный

513 / 145 / 27

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Записей в блоге: 15

28.12.2018, 22:04

makardasdasd, есть, например программа wing 101 — для работы с кодом
умеет форматировать текст

Garry Galler

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Записей в блоге: 1

28.12.2018, 22:51

Сообщение от makardasdasd

SyntaxError: bad input on line 5

Компилятор не глючный — он просто под python 2. Нужно ж думать…
5 строчка — это print. В python 2 print пишется без скобок и у этой инструкции нет параметров. Отсюда и ошибка синтаксиса.

Python

Python 2.7.12 (v2.7.12:d33e0cf91556, Jun 27 2016, 15:19:22) [MSC v.1500 32 bit (Intel)] on win32
Type "copyright", "credits" or "license()" for more information.
>>> print ('maximum',end=" ")
SyntaxError: invalid syntax
>>>

0 / 0 / 0

Регистрация: 25.12.2018

Сообщений: 10

28.12.2018, 23:05

[ТС]

Я понял, теперь буду знать

Источник

How to resolve the syntax error: bad input?

I am trying to print the sum of even numbers, but I am seeing this error called syntax error: bad input why? Here is my code

num = range(1,40)

num[0]=1 num[1]=2

for j in range(2,41):

num[j]=num[j-1]+num[j-2]

total=0

for j in range(0,41):

print num[j]

if num[j]%2==0:

total=total+num[j]

else:

num[j]=num[j+1]

Answers

I think the mistake is in this part

if num[j]%2==0:

total=total+num[j]

else:

num[j]=num[j+1]

In python alignment is very important try to change your code like this

if num[j]%2==0:

total=total+num[j]

else:

num[j]=num[j+1]

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	#———————Syntax Errors ——————#

	################### Example 1 #######################
	#SyntaxError: bad input (‘
	#’)
	#Cause: Forgetting punctuation

	def say_hello()
	print «Hello world!»

	#This is a very common error. Python requires a colon at the
	#end of function definitions. Add it into the function above
	#after «say_hello()» and the error will go away.

	#You might find that your error doesn’t say exactly this.
	#The «bad input» is whatever text follows the missing
	#punctuation. If you have a bad input error, no matter
	#what it says in the parentheses, you should check your
	#punctuation.

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May-14-2020, 07:40 AM
(This post was last modified: May-15-2020, 06:24 AM by snippsat.)

def __init__(self, name, gender, hp,attack, mp,exp,level): 
      '''Use double underscores'''
      #This method initializes the attibutes of the Character class
      self.name = name
      self.gender = gender
      self.hp = hp
      self.attack = attack
      self.mp = mp
      self.exp = exp
      self.level = level
      #these are the Character's stats.
    def __str__(self):
      return(str(self.name)+":  level "+str(self.level)++str(self.hp)+" hp, ")
      '''To be used in battle'''
    def level_check(self):
      if self.level==0:
        level_exp=50
      if self.exp>=level_exp:
        self.level=self.level+1
        level.exp=level.exp*3
        stat_points=5
        while stat_points>0:
          #put something here later
  chara1=Chara(input("What is your name?"),input("Are you a boy or a girl? nt 1. Boy nt  2. Girl"),9,3,0,0,0)

This is my code. On the last line, there is a «SyntaxError: bad input on line 53 in main.py.» I’ve looked through it and found that the problem has to do with my use of the inputs. I can’t find what’s wrong please help.

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Don’t post multiple threads, and use proper code tags please.
Can you show the line 53 of your code?

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(May-14-2020, 10:12 AM)pyzyx3qwerty Wrote: Can you show the line 53 of your code?

This is it:
chara1=Chara(input(«What is your name?»),input(«Are you a boy or a girl? nt 1. Boy nt 2. Girl»),9,3,0,0,0)

Also, I did not think that I posted it twice.

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The error is on line 52 where you don’t have anything inside the while statement. Just add a «pass» command to stub out the code for later

            while stat_points>0:
                pass

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(May-14-2020, 03:59 PM)Impropabletank Wrote: Also, I did not think that I posted it twice.

https://python-forum.io/Thread-Bad-input

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