Ошибка syntax error unrecognized expression

Why do I get this error and how can I test for it so it wont break, I tried checking for null but obviously that wont work, thanks.

Please don’t advice to not write the ID like this as I know its wrong but it is a possibility.

var jsonTest = [
  {
    "myId": "''''''""""'''''''''''''"#####$'''''",
  }
];

alert(jsonTest[0].myId); 
// Works - alerts the myId

$('#' + jsonTest[0].myId ).length; 
// Error: Syntax error, unrecognized expression:
// #''''''""""'''''''''''''"#####$'''''

Stan James's user avatar

Stan James

2,5151 gold badge28 silver badges35 bronze badges

asked Mar 11, 2013 at 12:36

Hello-World's user avatar

Hello-WorldHello-World

9,18923 gold badges87 silver badges153 bronze badges

0

jQuery’s uses this code to detect an id based selector :

characterEncoding = "(?:\\.|[\w-]|[^\x00-\xa0])+"
...
"ID": new RegExp( "^#(" + characterEncoding + ")" ),

This regex fails for "''''''""""'''''''''''''"#####$'''''" or more simply for "'".

The query engine is limited, which isn’t very surprising for a so concise language and id validity rules so lax. it can’t handle any valid id.

If you really need to be able to handle any kind of valid id, use

$(document.getElementById(jsonTest[0].myId))

In fact, you should never use $('#'+id) as it simply adds a useless (and a little dangerous) layer of parsing for the same operation.

answered Mar 11, 2013 at 12:39

Denys Séguret's user avatar

Denys SéguretDenys Séguret

370k85 gold badges775 silver badges752 bronze badges

3

If I understood your question, you have an ID that contains special characters. You basically need to escape them so they’re treated as literal characters rather than query selectors:

To use any of the meta-characters ( such as
!»#$%&'()*+,./:;<=>?@[]^`{|}~ ) as a literal part of a name, it must
be escaped with with two backslashes: . For example, an element with
id=»foo.bar», can use the selector $(«#foo.bar»).

… and in this case you also need an additional escaping level for the string delimiter, ". It’s crazy but this works:

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head><title></title>
<script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.min.js"></script>
<script type="text/javascript"><!--
jQuery(function($){
    console.log( $("#" + "\'\'\'\'\'\'\"\"\"\"\'\'\'\'\'\'\'\'\'\'\'\'\'\"\#\#\#\#\#\$\'\'\'\'\'").length );
});
//--></script>
</head>
<body>

<div id="''''''&quot;&quot;&quot;&quot;'''''''''''''&quot;#####$'''''">Foo</div>

</body>
</html>

Edit: Of course, dystroy’s answer —omit jQuery selection engine and use getElementByID()— is way more practical. jQuery manual links an interesting blog entry that covers this and other related techniques:

document.getElementById() and similar functions like
document.getElementsByClassName() can just use the unescaped attribute
value, the way it’s used in the HTML. Of course, you would have to
escape any quotes so that you still end up with a valid JavaScript
string.

answered Mar 11, 2013 at 13:07

Álvaro González's user avatar

Álvaro GonzálezÁlvaro González

141k40 gold badges259 silver badges356 bronze badges

W3C has defined a new function for this this: CSS.escape(). In your example code, it would look like this:

var jsonTest = [
  {
    "myId": "''''''""""'''''''''''''"#####$'''''",
  }
];

$('#' + CSS.escape(jsonTest[0].myId)).length; // Works 

Browsers don’t yet support it, but there is a polyfill library that you can use in the mean time:
https://github.com/mathiasbynens/CSS.escape

I’ve used it with success in my project.

answered Sep 30, 2015 at 17:54

Stan James's user avatar

I faced this error while upgrading from jquery 1.6 to jquery 3.6.
I got this error in flexigrid library. The fix to this problem is simple as mentioned in above answers.

You need to escape all special characters and unescape them if needed to show in a grid or for further processing.

The code looks like:

var str = "abc@abc.com";

//make str value to, basically escape all special chars : "abc/@abc/.com"
str = str.replace(/[.*+?^$@%{}()|[]\]/g, '\$&');

//do some processing

//revert str value to: "abc@abc.com"
str = str.replaceAll("\", ""); 
                                    

answered May 11, 2021 at 10:39

Prasad Bhalerao's user avatar

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Доброго времени суток, возникло 2 вопроса.
1) при клике на логотип сайт, который имеет якорь «#» и отправляет на верх сайт, выдаётся ошибка.(ругается на 4-ю строчку)
Текст ошибки:

Uncaught Error: Syntax error, unrecognized expression: #(…) — «jquery.js?ver=1.12.4:2

2) В 8й строке, у меня происходит переход на главную страницу и мне нужно выполнить оставшийся код, который идёт после else. Проблема в том, что этот код выполняется моментально, а мне нужно сделать так, чтобы он выполнялся только после того, как произойдёт переход на страницу.
af82cc62afbc41acb607037f24902b18.png
eeb081cd8aae4b3585658d0274155d62.png

jQuery(function($) {
var homepage = 'http://rcamedia.ru/';
$('a[href*=#]').live('click', function(event) {
  var attrib = $(this).attr('href');
  console.log(attrib);
    if($("div").is(attrib)) {}
     else {
      document.location = homepage;
    }
    event.preventDefault();
    var target_offset = $(this.hash).offset() ? $(this.hash).offset().top : 0;
    //change this number to create the additional off set
    var customoffset = 85;
    $('html, body').animate({scrollTop:target_offset - customoffset}, 500);
    console.log("Done!");
});

}(jQuery));

Answer by Vienna Greer

If you are using jQuery1.9, the problem may lie in the content being loaded. There is a new update which requires that the first character in the response be a < [AKA the less than symbol]. Even whitespace will cause this to break and throw the dreaded «Uncaught Error: Syntax error, unrecognized expression:» error.,Find centralized, trusted content and collaborate around the technologies you use most.,

Will the net current drawn by a microcontroller equal the current supplied by it

,Asking for help, clarification, or responding to other answers.

If I’m doing that :

$.ajax('/',function(html){
  html = $('<div></div>').append(html);
  $(html);
});

It works fine.
If I do :

$.ajax('/',function(html){
  $(html);
});

It gives me a (through the FF error console) :

Erreur : Error: Syntax error, unrecognized expression: <div id="...">(...)
jquery.min.js - line : 4

So I now do something like :

$.ajax('/',function(html){
  $($.parseHTML(html));
});

Answer by Aydin Ibarra

I’m trying to retrieve data through .ajax call and add the response html code to bootstrap modal body. But I kept receiving this error:,Actually I do receive the desired data in response, but because of this error, the data cannot be displayed on modal window. ,Here is my code. When I click a link, the ajax call returns a html form and inserts it into modal body. Then the modal window is shown.,I have been googling and changing the code for several hours but still no luck. I would highly appreciate it if anyone can give me some idea. Thanks in advance!

Here is my code. When I click a link, the ajax call returns a html form and inserts it into modal body. Then the modal window is shown.

<a href="{{route('menu.create')}}" class="btn btn-default pull-right show-new-menu-item-modal" data-toggle="modal">New Menu Item</a>

$('body').on('click', '.show-new-menu-item-modal', function(event) {
event.preventDefault();
 $.ajax({
        url: $(this).attr('href'),
        dataType: 'html',
        success: function(response) {
            $("#new-menu-item-body").html(response);
        }
    });
    $('#new-menu-item-modal').modal('show');
});

Answer by Daniella Beil

© 2013 jQuery Foundation

<html><body><div id="error">Desolee, Adresse e-mail incorrect.Desolee, Entrez votre nom</div></body></html>

Answer by Wallace English

How to I resolve unrecognized expression?,If I use Java’s ‘MediaServletTree’, I get ‘Uncaught Error: Syntax error, unrecognized expression: {“id”:“demo_child_1”,“text”:“Child 1”}’.,Powered by Discourse, best viewed with JavaScript enabled,My code in Java for MediaServletTree:

My javascript:


$('#treeFolderName').jstree({
                    "core" : {
                      'data' : {
                        'url' : function (node) {
                            return node.id === '#' ?
                              '../MediaServletTree' : '../MediaServletTree';
                              //'ajax_demo_children.json' : 'ajax_demo_children.json';
                        },
                        'data' : function (node) {
                          return {
                              'id' : node.id
                          };
                        }
                      }
                    }
             });

My code in Java for MediaServletTree:


JSONObject jsonObj = new JSONObject();
jsonObj.put("id", "demo_child_1");
jsonObj.put("text", "Child 1");
out.print(jsonObj);


Answer by Jedidiah Rhodes

Parsing jQuery Ajax response
,
JQuery and Ajax response headers
,
ajax — Parsing JSON response using jquery
,this is the output of console.log(success); and the red box is what I want from the response…

I need to post data to a php page and then I’d like to get the text of a certain div that is in the response but I can’t seem to set things up correctly. I’m not too good with jQuery but I can usually figure things out fairly quickly… I’ve been at this for a minute and have tried everything I have found… I think I am just missing the right combination of stuff.

$.post("process.php", data , function (response) {  

       var w = window.open();    

       $(w.document.body).html(response); 

       console.log(typeof response); //  yeilds string 
       //create jquery object from the response html
       // var $data = $(response);   // yeilds Uncaught Error: Syntax error, unrecognized expression: + whole html text


       var success =  $($.parseHTML(response)).find("#success"); 
       console.log('success'); 
       console.log(success);        // see screenshot
       console.log(success.text()); // yields nothing 
       console.log(success.val());  // yields undefined 
       // if (window.focus) {w.focus()}; 

 },'html');  

and this does that:

var success =  $(response).find("#success"); 
console.log('success'); 
console.log(success);        // yeilds Uncaught Error: Syntax error, unrecognized expression: + whole html text in red

Response is…

<html><head>
   <style>

      div.totals {
          font-family:calibri; font-size:.9em;  display:inline-block; 
          border-width: 2px;  border-style: solid; border-color: #FFD324; 
          background-color: #FAF5D7; color: #514721; 
          width: 500px; 
          }

      div.error_invalid {
         font-family:calibri; font-size:.9em;  display:inline-block; 
         border-width: 2px; border-style: solid; border-color: #9999CC; 
         background-color: #EEEEFF; color: #7979B8; 
     }

    </style>
    </head>
    <body>
    <div class="totals">Total new rows added: 0 out of 0<br/></div>
    <br/><br/>
    <div class="totals">Total updated rows: 0 out of 0 <br/></div>

    <div id="success">true</div>
    </body></html> 

Answer by Presley Portillo

3. Although the error handler .fail()is defined, you will still see the syntax error Uncaught Error: Syntax error, unrecognized expression: {«code»:»rest_no_route»,»message»:»No route was found matching the URL and request method»,»data»:{«status»:404}},Now if you deactivate Wordfence, the request error will gracefully be handled.,Steps to reproduce:
1. Open the console in wp-admin with Wordfence active.
2. Run this code which results in an error (404), because of v1 instead of v2,I did a bit of snooping myself and found the exact line where the error is raised:

Steps to reproduce:
1. Open the console in wp-admin with Wordfence active.
2. Run this code which results in an error (404), because of v1 instead of v2

jQuery.ajax({
  type: 'GET',
  url: location.origin + '/wp-json/wp/v1/posts',
  contentType: 'application/json; charset=utf-8',
  dataType: 'json',
})
.then(data => console.log(data))
.fail(jq => console.log(jq));

Answer by Matteo Hail

With the conversion to Editor 1.5, I am unable to edit any rows. I get errors like:,What is really interesting is that jQuery’s selectors shouldn’t actually be getting invoked at all here with the latest DataTables versions.,As a little workaround for the moment, could you try the following — in the dataTables.editor.js file find:,Thanks for the workaround code, Allan. I haven’t tried it yet since I am using a single, minified file from the awesome new DataTables Downloader.

AJAX Load:

{
    "draw" : 1,
    "recordsTotal" : 3,
    "recordsFiltered" : 3,
    "data" : [
        [
            "{"P":"AAAX88AAJAAAAGXAAA","K":{"ID":1}}",
            1,
            "Administrator",
            "TableMan Administrators-1"
        ],
        [
            "{"P":"AAAX88AAJAAAAGXAAB","K":{"ID":2}}",
            2,
            "Test Group2",
            "Includes a few more tables"
        ],
        [
            "{"P":"AAAX88AAJAAAAGXAAC","K":{"ID":3}}",
            3,
            "3rd Groupx2",
            "Includes yet more tables"
        ]
    ]
}

Request:

{
    "action" : "edit",
    "data" : {
        "{"P":"","K":{"Id":4}}" : {
            "EditorId" : "-6",
            "AccountId" : "1",
            "EventType" : "L",
            "LogSqlId" : "0",
            "LogIpAddressId" : "1",
            "UtcTime" : "09/02/2015 4:59 PM"
        }
    }
}

Response:

{
    "data" :
    [
        [
            "{"P":"","K":{"Id":4}}",
            4,
            -6,
            1,
            "L",
            0,
            1,
            "2015-09-02T16:59:00"
        ]
    ]
}

Chrome’s trace (at least, it looks like a trace to me):

Uncaught Error: Syntax error, unrecognized expression: #{"P":""
Sizzle.error @ jquery-2.1.4.js:1458
Sizzle.tokenize @ jquery-2.1.4.js:2075
Sizzle.compile @ jquery-2.1.4.js:2446
Sizzle.select @ jquery-2.1.4.js:2536
Sizzle @ jquery-2.1.4.js:855
Sizzle.matches @ jquery-2.1.4.js:1396
jQuery.filter @ jquery-2.1.4.js:2672
winnow @ jquery-2.1.4.js:2655
jQuery.fn.extend.filter @ jquery-2.1.4.js:2704
(anonymous function) @ tm.min.js:175Za @ tm.min.js:172
(anonymous function) @ tm.min.js:174
h.extend.iterator @ tm.min.js:162
(anonymous function) @ tm.min.js:174
t.extend.g @ tm.min.js:165
(anonymous function) @ tm.min.js:178
t.extend.g @ tm.min.js:165
E.dataTable.commit @ tm.min.js:424
f._dataSource @ tm.min.js:402
(anonymous function) @ tm.min.js:415
(anonymous function) @ Editor?id=9:83
jQuery.Callbacks.fire @ jquery-2.1.4.js:3099
jQuery.Callbacks.self.fireWith @ jquery-2.1.4.js:3211
done @ jquery-2.1.4.js:8264
jQuery.ajaxTransport.options.send.callback @ jquery-2.1.4.js:8605
browserLink:37 XHR finished loading: GET "http://localhost:61071/dc7f0afe6d5c4ba592d097da5a0d5fca/arterySignalR/ping?…KHTML%2C+like+Gecko)+Chrome%2F45.0.2454.85+Safari%2F537.36&_=1442619094666".p.support.ajax.p.ajaxTransport.c.send @ browserLink:37p.extend.ajax @ browserLink:37i.transports._logic.pingServer @ browserLink:62(anonymous function) @ browserLink:62

Answer by Lucian Melton

If the AJAX response have some space before the HTML start tag
jQuery will throw this error.
Emmmmmmm…, I found two way to fix it, make sure server response <!DOCTYPE HTML> as response first start string,
or plugin trim the response string before call
e = $(this.itemsContainerSelector, b.trim()).eq(0),Thank you for your report. I don’t want to bloat the plugin with fixes for everything that can go wrong with a website, but I will take it into consideration.,
Uncaught Error: Syntax error, unrecognized expression: <!DOCTYPE HTML> when has space before <!DOCTYPE HTML>
,If you have questions, feedback or think this issue was closed by mistake, please comment on this issue.

If the AJAX response have some space before the HTML start tag
jQuery will throw this error.
Emmmmmmm…, I found two way to fix it, make sure server response <!DOCTYPE HTML> as response first start string,
or plugin trim the response string before call
e = $(this.itemsContainerSelector, b.trim()).eq(0)

<!DOCTYPE HTML>

If the AJAX response have some space before the HTML start tag
jQuery will throw this error.
Emmmmmmm…, I found two way to fix it, make sure server response <!DOCTYPE HTML> as response first start string,
or plugin trim the response string before call
e = $(this.itemsContainerSelector, b.trim()).eq(0)

e = $(this.itemsContainerSelector, b.trim()).eq(0)

jquery-errors-post

Let’s face it, nobody is perfect! Everyone makes mistakes now and then and jQuery is the same – although they have an excellent bug fixing team who are fixing up errors and enhancing jQuery around the clock errors may appear from time to time.

In light of this and the fact that I’ve been developing with jQuery for quite a while now and every now and then an error will show in the Firebug Console and “I have to Google it”. I thought I would share some of the most common jQuery errors so that when you encounter them you might have some idea of how to solve the puzzle.


Error: “jquery.1.4.2.js error “a is null””

jquery.1.4.2-error

Possible Causes

a is null
[Break On This Error] a))();else c.error("Invalid JSON: "+a)...(d)if(i)for(f in a){if(b.apply(a[f],
jquery....min.js (line 29)

I was thinking it might have something to do with this line failing because there was no matches.

$.each(rawData.match(secureQueryRegex), function(index, currentQuery)

Then, I was thinking it may have been the size of data as it was 69,443 characters long…

Possible Solutions

But I eventually found out it was bad characters inside the data string (which was grabbed directly from HTML). See cleanHTML() function to remove bad characters form HTML.

rawData =  rawData.replace(/[^<>a-zA-Z 0-9]+/g,'');  /* clean up for match() statement */

Specific Versions

Seen in 1.4.2


Error: “SyntaxError: invalid object initializer”

invalid-object-init

Possible Causes

Object declaration syntax error.

$.getScript(
{
	'http://www.domain.com/js/preview.js'
});

OR

$("div").css(
{
    padding:'0',
    margin,'4px'
});

Possible Solutions

Remove the brackets the getScript() function can be called with just the url. The same applies to any other object declaration or function call with an object that doesn’t accept one.

$.getScript('http://www.domain.com/js/preview.js');

Change the comma to a semi colon.

$("div").css(
$("div").css(
{
    padding: '0',
    margin: '4px'
});

Specific Versions

Seen in 1.4.2


Error: “uncaught exception: Syntax error, unrecognized expression: [object HTMLLIElement]”

syntax-error

Possible Causes

This seems like a jQuery selector error. It seems to appear more frequently in v1.4.2 or earlier so try updating to the latest version of jQuery.

$(this+' a').css(
var req = $("input[@name=required]").val();

Possible Solutions

Not sure but take a look at your selectors and make sure they work properly. Try including the full jQuery versions first to get better error info on what might be causing the problem.

@ is old selector syntax.

var req = $("input[name=required]").val();

Specific Versions

Seen in 1.4.2


Error: “SyntaxError: missing ) after argument list”

no-idea

Possible Causes

Missing off closing brackets or curly braces.

})(jQuery

Possible Solutions

})(jQuery);

Specific Versions

Seen in 1.4.2


Error: “SyntaxError: missing : after property id”

mssing-property-id

Possible Causes

This is a repeat of the object initialize error but it’s caused by Using curly brackets when they are not needed.

$.getScript(
{
	'http://www.domain.com/js/preview.js', function(data, textStatus){
   console.log(data); //data returned
   console.log(textStatus); //success
   console.log('Load was performed.');
});

Possible Solutions

$.getScript('http://www.domain.com/js/preview.js', function(data, textStatus)
	{
	   console.log(data); //data returned
	   console.log(textStatus); //success
	   console.log('Load was performed.');
	}
);

Specific Versions

Seen in 1.4.2


Error: “TypeError: jsSrcRegex.exec(v) is null”

Possible Causes

Caused by double exec on same regex OR caused by invalid html “jsSrcRegex.exec(v) is null”.

console.log(jsSrcRegex.exec(v));
console.log(jsSrcRegex.exec(v)[1]);

Possible Solutions

Check the html first:

if(jsSrcRegex.exec(html)){ 
	console.dir(jsSrcRegex.exec(html)[1]);
}

OR

Use recompile the regex:

console.log(jsSrcRegex.exec(v));
jsSrcRegex.compile();
console.log(jsSrcRegex.exec(v)[1]);

Specific Versions

n/a


Error: “XML descendants internal method called on incompatiable object”

xml-error

Possible Causes

Double full stop in jQuery chain commands.

$('.'+inElem)..removeClass('mouseover').addClass('selected');

Possible Solutions

To fix simply remove the double full stop.

Specific Versions

n/a


Error: “undetermined string literal”

You may have seen this one before! :)
string-error

Possible Causes

Many possible causes: could be that you put code where a selector should be or multiple line strings or wrong string format (bad characters) or angle brackets etc.

Possible Solutions

See jQuery Undetermined String Literal Error for a very detailed explanation on this error!

Specific Versions

n/a


Error: “Syntax Error: Unrecognized Expression”

jquery-error-unrecognised-expression

Possible Causes

Missing attribute name in selector.

$('input["depDate"]').val(departureDate);

Possible Solutions

Add in the name attribute (or id, class etc) into the selector.

$('input[name="depDate"]').val(departureDate);

Specific Versions

n/a


Error: “SyntaxError: syntax error”

string-error
(click image to enlarge)

Possible Causes

Well, this error is very generic and there might be a number of reasons why is happens but in this example you can clearly see it was caused by an extra “+” in the jQuery selector.

$('.itemColumn'+currentColNum+).append(v);

Possible Solutions

Unfortunately, on this one you’ve just got to carefully check through your syntax and make sure you don’t have any mistakes. Try using something like jshint or another js checker to assist.

$('.itemColumn'+currentColNum).append(v);

Specific Versions

n/a


Error: “(d || “”).split is not a function”

live-hover-error

Possible Causes

Sorry, I found this error and took a screenshot but can’t remember how i got it! I think it might be a live image hover bug in jQuery 1.4.2 but not sure.

Here is something bug 862 similar which i found (it was logged 5 years ago aha).

Sometimes you see a similar error which reads “jquery error d is undefined” or such which I saw a few times in jQuery 1.5.

Possible Solutions

Update to latest version of jQuery.

Specific Versions

Seen in 1.4.2


Error: “Syntax error, unrecognized expression: >”

error1b

Possible Causes

if ($('#'+$form).length == 0)
{
    ...
}

if ($('#'+$form))
{
    ...
}

Possible Solutions

Don’t try to use html as a jQuery selector element.

Specific Versions

Seen in 1.7.1


Error: “Syntax error, unrecognized expression: #[object Object]”

error2

Possible Causes

Using an DOM element as a jQuery selector element.

$('#'+$form)

Possible Solutions

Check your jQuery selectors are correct.

Specific Versions

Seen in 1.7.1


Error: “Syntax error, unrecognized expression: name”

error-expression-name

Possible Causes

var code = $(':input:name=["disCode"]').val();

Possible Solutions

Move square bracket before attribute name.

var code = $(':input:[name="disCode"]').val();

Specific Versions

Seen in 1.7.2


Error: “XML descendants internal method called on incompatible Object”

XML descendants internal method called on incompatible Object

Possible Causes

discElem..parent().after(data.html);

Possible Solutions

discElem.parent().after(data.html);

Specific Versions

Seen in 1.7.2


Error: “SyntaxError: invalid label”

SyntaxError invalid label

Possible Causes

Using a colon at the end of a statement.

console.log(count):

Possible Solutions

Use a semi colon instead of a colon.

console.log(count);

Specific Versions

Seen in 1.7.2


Error: “TypeError: emails.match(/@/gim) is null”

TypeErroremailsmatch

Possible Causes

Using .length function on a regular expression which has no matches.

var emails = '',
    count = emails.match(/@/igm).length;

Possible Solutions

If you reference the length property after then it simply returns undefined and no error. If you use the following you will see the error: “TypeError: count is null”.

var emails = '',
    count = emails.match(/@/igm),
    length = count.length;

If you check the count is not null before assigning the value it does not error and will give you 0 for a no count.

var emails = '',
    regex = /@/igm,
    count = emails.match(regex),
    count = (count) ? count.length : 0;

Specific Versions

Seen in 1.7.2


Error: Error in Actionscript. Use a try/catch block to find error.”

Possible Causes

Using a call on a Flowplayer or Flash based Object with errors.

$f('fms2').toggleFullscreen();

Possible Solutions

Try checking the initialisation code for the Flash Object.

Specific Versions

Seen in 1.7.2


After seeing all those errors, here’s something to cheer you up!

smiley-face

Or you can see more errors and bugs on the Official jQuery Bug Tracker.

If you find any errors please leave a comment with the error and solution and i will add it to the list!

Cheers!


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