Ошибка макроса subscript out of range

 

tgg

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Добрый вечер знатоки. Простой макрос стал прерываться ошибка runtime error 9 subscript out of range, долго искал причину.. а оказалось дело в следующем. При открытии другой Книги, или работая в другой книге в момент когда запускаются макросы (2 шт.каждые 60сек) в Книге1 и вылетает error

Изменено: tgg16.03.2018 10:48:28

 

А где собственно вопрос?

С уважением,
Федор/Все_просто

 

tgg

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#3

27.03.2015 20:31:46

На строке With Worksheets(«Лист1») всё и происходит!
Что надо изменить в коде (?) для работы одновременно в разных Книгах EXCEL

Код
Sub ShowWatch()     
ThisWorkbook.Sheets(1).Range("F1").Value = Now - Date     
Application.OnTime Now + TimeSerial(0, 0, 60), "ShowWatch"     
Application.OnTime Now + TimeSerial(0, 0, 60), "Proverka" 
End Sub 

Private Sub "Proverka"() 
With Worksheets("Лист1")             
If [I2] = "a" Then                 
Exit Sub             
 End If             
If [J2] <> "Ok" Then                 
Exit Sub             
 End If 
OtpravkaPisma     
[I2] = "a"     
[G2] = [D139]     
[G2].Value = [G2].Value         
End With End Sub

Изменено: tgg31.03.2015 22:50:24

 

Казанский

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#4

27.03.2015 20:46:12

Начало второй процедуры:

Код
Private Sub Proverka()
With ThisWorkbook.Worksheets("Лист1")
  If .Range("I2") = "a" Then

Аналогично переделайте все квадратные скобки.

 

tgg

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Вот в чём вопрос??
Пол часа полёт нормальный!
Спасибо огромное, все работает.
Но мучает вопрос, в чем косяк случился?

Изменено: tgg31.03.2015 22:50:35

 

1. Worksheets(«Лист1»)  — без указания принадлежности к книге, относится к активной в момент запуска макроса книге. Видимо, в ней нет листа Лист1.
2. Оператор With фактически не работает, т.к. нигде нет обращения к свойству или методу, начинающегося с точки.
3. [I2], т.е. Range(«I2») — без указания листа, относится к активному в момент запуска макроса листу.

 

tgg

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Еще раз огромное спасибо!!

 

Юрий М

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Сообщений: 60781
Регистрация: 14.09.2012

Контакты см. в профиле

tgg, два момента:
1. Свои коды оформляйте соответствующим тегом — посмотрите, как выглядит код у Казанского.
2. Не нужно цитировать всё подряд.

 

tgg

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#9

19.06.2015 22:03:22

Доброго времени суток! Не прошло и полгода …. Я к Вам с поклоном и вопросом.
Макрос в модуле листа из этой темы (

http://www.planetaexcel.ru/forum/?FID=8&PAGE_NAME=read&TID=30902

), с той лишь разностью, что работает с диапазоном — If Not Intersect(ActiveCell, Range(«E18:E27»)) Is Nothing Then. Вот собственно сам макрос:

Код
Option Explicit 

Private Sub Worksheet_SelectionChange(ByVal Target As Range) 
    If Not Intersect(ActiveCell, Range("E18:E27")) Is Nothing Then 
        Call Module1.Spravka 
    End If 
End Sub 

Но старая песня, опять при открытии другой книги excel этот макрос зачем-то срабатывает и встаёт на 2 строке.
Подскажите пожалуйста, как его поправить!?!
Спасибо!

 

Johny

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Когда открывается книга, то она становится активной, и поэтому Ваш диапазон Range(«E18:E27») относится уже к ОТКРЫТОЙ книге.

There is no knowledge that is not power

 

tgg

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Пробовались разные варианты, это первый вариант макроса, с указанием листа и принадлежности к книге. Но результат всегда был один и тот же.

 

Johny

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#12

19.06.2015 22:20:38

Цитата
tgg написал: Пробовались разные варианты

Ну так покажите эти «разные» варианты.

There is no knowledge that is not power

 

tgg

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Так они ведь не работают как надо!

 

Rjn

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#14

16.03.2018 09:08:30

Добрый день!
В макросах новичок, второй день разбираюсь.
Подскажите  пожалуйста.
Есть макрос который из одного файла переносит информацию в другой файл.
Другой файл называется «Система прогнозирования свободных остатков_пробный.xlsm»
Если этот файл открыт, то  данные переносятся, если файл закрыт, то данные не переносятся и выходит ошибка subscript out of range
Ниже макрос

Код
Dim sbor As Range

Sub PerenosSbor()
   Dim lStart As Long, lEnd As Long, lLastRow As Long

   Application.ScreenUpdating = False
   Application.EnableEvents = False

  Workbooks("Система прогнозирования свободных остатков_пробный.xlsm").Save

   Application.Wait (Now + TimeValue("0:00:3"))

   '1. Определение первой ячейки с данными в столбце "A".
   'After:=Cells(Rows.Count, "A") указывает, с какой ячейки начать поиск.
   'Если не указывать, то поиск ведётся с ячейки "A1" и первой просматриватся
   'ячейка "A2". Если данные уже есть в ячейке "A1", то результат
   'будет неправильным. Поэтому нужно указать ячейку, с которой начинается поиск.

   lStart = Columns("A").Find(What:="?", After:=Cells(1, "A"), _
       LookIn:=xlValues, LookAt:=xlPart, SearchOrder:=xlByColumns, _
       SearchDirection:=xlNext, MatchCase:=False, SearchFormat:=False).Row

   '2. Определение последней ячейки с данными в столбце "A".

   lEnd = Columns("A").Find(What:="?", LookIn:=xlValues, LookAt:=xlPart, _
       SearchOrder:=xlByColumns, SearchDirection:=xlPrevious, _
       MatchCase:=False, SearchFormat:=False).Row

   '3. Выделение диапазона с данными в столбце "A".

  Set sbor = Range("A" & lStart & ":G" & lEnd)

With Workbooks("Система прогнозирования свободных остатков_пробный.xlsm").Worksheets("1.СБОР")
lLastRow = .Cells(.Rows.Count, 1).End(xlUp).Row + 1
On Error Resume Next
.ShowAllData
sbor.Copy
.Range("A" & lLastRow).PasteSpecial xlPasteValuesAndNumberFormats
End With

Workbooks("Система прогнозирования свободных остатков_пробный.xlsm").Save
   Application.ScreenUpdating = True
   Application.EnableEvents = True
End Sub
 

Rjn

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В чем ошибка???
На сколько я знаю  историю создания макроса, данный макрос так же  писал не профи)

 

Hugo

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Ведь естественно — если файл закрыт, то при попытке его сохранения должна быть ошибка.

 

Sanja

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#17

16.03.2018 09:19:33

Цитата
Rjn написал: В чем ошибка?

Вы же выше сами написали, что

Цитата
Rjn написал: Если этот файл открыт, то  данные переносятся, если файл закрыт, то данные не переносятся

Макрос написан именно так, что файл должен быть предварительно открыт

Согласие есть продукт при полном непротивлении сторон.

 

Rjn

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Регистрация: 16.03.2018

А где и как исправить макрос, что бы он работал при закрытом  файле?

 

vikttur

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Сообщений: 47199
Регистрация: 15.09.2012

1. Код в сообщении  следует оформлять кнопкой <…>
2. Не нужно форматировать шрифт мелким. Стандартный нормально смотрится.

 

vsahno

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Регистрация: 22.07.2017

#20

21.02.2019 19:08:28

Цитата
tgg написал:
Так они ведь не работают как надо!

У меня не были прописаны ПОЛНЫЕ ИМЕНА ФАЙЛОВ! — только название, без расширения:
Workbooks(«Авторизация»).Worksheets(«Лист8»)
НА моем компе макросы работали как надо! НО при установке у клиента … как там — …»runtime error 9 subscript out of range». Главное у них и по сети на 1 компе все прекрасно работало!!!
Пока додумался до: Workbooks(«Авторизация.xlsm»).Worksheets(«Лист8») —  больше часа убил и вспотел! :)

 

Дмитрий Минин

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#21

21.03.2023 10:15:59

Добрый день!
Подскажите, как исправить ошибку, мозгов не хватает понять и разобраться?!

Код
Sub GetCoordinates()
    Dim fso As Object
    Dim objShell As Object
    Dim objFolder As Object
    Dim objFile As Object
    Dim strPath As String
    Dim arrDetails As Variant
    Dim latRef As String, lonRef As String
    Dim latDeg As Double, latMin As Double, latSec As Double, lonDeg As Double, lonMin As Double, lonSec As Double, alt As Double
    Dim i As Integer
    
    'Путь к файлу
    strPath = "C:UsersMininDODesktopExifTool-54_[10].JPG"
    
    'Создание объектов
    Set fso = CreateObject("Scripting.FileSystemObject")
    Set objShell = CreateObject("Shell.Application")
    Set objFolder = objShell.Namespace(fso.GetParentFolderName(strPath))
    Set objFile = objFolder.ParseName(fso.GetFileName(strPath))
    
    'Получение деталей файла
    arrDetails = Split(objFolder.GetDetailsOf(objFile, 27), ";")
    
    'Извлечение координат
    For i = 0 To UBound(arrDetails)
        If InStr(arrDetails(i), "GPS Latitude Ref") > 0 Then
            latRef = arrDetails(i + 1)
        ElseIf InStr(arrDetails(i), "GPS Latitude") > 0 Then
            latDeg = CDbl(Split(arrDetails(i + 1), "°")(0))
            latMin = CDbl(Split(arrDetails(i + 1), "°")(1))
            latSec = CDbl(Split(Split(arrDetails(i + 1), "°")(2), ".")(0))
        ElseIf InStr(arrDetails(i), "GPS Longitude Ref") > 0 Then
            lonRef = arrDetails(i + 1)
        ElseIf InStr(arrDetails(i), "GPS Longitude") > 0 Then
            lonDeg = CDbl(Split(arrDetails(i + 1), "°")(0))
            lonMin = CDbl(Split(arrDetails(i + 1), "°")(1))
            lonSec = CDbl(Split(Split(arrDetails(i + 1), "°")(2), ".")(0))
        ElseIf InStr(arrDetails(i), "GPS Altitude") > 0 Then
            alt = CDbl(Replace(arrDetails(i + 1), " m", ""))
        End If
    Next i
    
    'Преобразование координат в десятичные градусы
    If latRef = "S" Then
        latDeg = -latDeg
    End If
    If lonRef = "W" Then
        lonDeg = -lonDeg
    End If
    latDeg = latDeg + (latMin / 60) + (latSec / 3600)
    lonDeg = lonDeg + (lonMin / 60) + (lonSec / 3600)
    
    'Вывод координат в ячейки Excel
    Sheets("Sheet1").Range("A1").Value = latDeg
    Sheets("Sheet1").Range("B1").Value = lonDeg
    Sheets("Sheet1").Range("C1").Value = alt
    
    'Очистка объектов
    Set fso = Nothing
    Set objShell = Nothing
    Set objFolder = Nothing
    Set objFile = Nothing
End Sub

Прикрепленные файлы

  • Безымянный.jpg (228.87 КБ)

 

Существует ли лист «Sheet1» в активной книге?

 

Дмитрий Минин

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#23

21.03.2023 11:00:04

Цитата
написал:
Существует ли лист «Sheet1» в активной книге?

Понял ошибку и уже исправил.

Sometimes when we write and attempt to run sub-procedures in Excel VBA, Excel VBA returns a message box with the error message “Runtime error 9: Subscript out of range.” 

subscript out of range error

The “Subscript out of range” error happens when we reference a non-existent collection member or a non-existent array element.

By the error, Excel VBA is telling us, “I have not found what you are looking for.”

This tutorial gives examples of specific causes of this error and how to fix it.

Before fixing the “Subscript out of range” error, you must identify its cause.

When you press the Debug button on the error message box, Excel VBA takes you to the statement that caused the error. By examining the line of code, you should be able to tell what caused the error. We outline some of the causes and solutions below. 

Cause #1: Referencing a Non-Existent Item in a Collection

We can only access members of collections within their delimited ranges.

Therefore, attempting to access a collection member outside the defined scope will cause the “Subscription out of range” runtime error. 

Suppose we have only Sheet1 and Sheet2 in our active workbook. 

sheets in the workbook

If we write the following sub-procedure and press F5 to run it:

We get the “Subscript out of range” error:

subscript out of range error

The error occurs because the Sheet3 object is not present in the Sheets collection, which consists of all the worksheets and chart sheets in the active workbook.

Therefore the code is referencing a non-existent entity in the Sheets collection.

How to Fix It

You can fix this error in any of the following ways:

  • Create the non-existent object; in this case, add Sheet3 to the workbook.
  • Check the spelling of the name of the collection member you want to access and ensure it is correct.
  • In the Excel VBA code, refer to an object present in the collection; in this case, you can refer to either Sheet1 or Sheet2. 
  • Use the For Each…Next loop instead of referencing specific collection members. The loop allows us to loop through collection members and repeat particular actions, such as unhiding worksheets.
Also read: Not Enough Memory to Complete This Action in Excel – How to Fix?

Cause #2: Attempting to Access a Closed Workbook

If you try to access a closed workbook, you get the “Subscript out of range” error.

For example, if we have a closed workbook called “Employees” on our computer, running the following sub-procedure will generate the “Subscript out of range” error.

Macro to activate closed workbook

This error is generated because a closed workbook is not part of the collection of workbooks.

All the open workbooks on your computer make up the workbooks collection. 

How to Fix It

You can use any of the following methods to fix the error. 

  • Open the workbook you want to access, then run the sub-procedure.
  • Use the For Each…Next loop to check whether the workbook you wish to access is open. The loop goes through all the available workbooks and matches the name of the workbook you want to access against each open workbook. If a match is found, the workbook is open otherwise; the workbook is closed.

Cause #3: Referencing a Non-existent Array Element 

If you reference a non-existent array element in your code, VBA displays the “Subscript out of range” to indicate something wrong with the code.

For example, the following code refers to an array element 11, which is not in the array declaration. 

incorrect array declaration

When we attempt to run the code, we get the “Subscript out of range” error.

How to Fix It

You can use any of the following techniques to solve the problem:

  • Verify the upper and lower bounds of the array in the array declaration. If the dimensions are different from what you intended, adjust them accordingly.
  • Ensure that you only refer to the array elements in the array declaration.
  • Use LBound and UBound functions to direct the access of redimensioned arrays. The LBound function returns the lower boundary of the array, which can be either 0 or 1. The UBound function returns the upper limit of the array, which is equivalent to the number of items in the array. 
  • If the array dimensions are declared variables, ensure the variable names are spelled correctly. 

Cause #4: Not Specifying the Number of Elements in an Array

If you declare an array but do not specify the number of elements in the array and attempt to access an element in the array,  VBA returns the “Subscript out of range” error.

For example, the following code results in the error:

number of arrays not declared

How to Fix It

  • Explicitly specify the number of elements in the array in the array declaration. 

Cause #5: Misspelling the name of a Workbook

If you misspell the name of the workbook you want to access, Excel VBA will return the “Subscript is out of range error.”

For example, if you want to activate a workbook named “Employees.xlsx,” the following code will not activate the workbook but return an error:

misspelled workbook name

Although the workbook is open, the sub-procedure does not activate it because its name needs to be corrected.

How to Fix It

  • Check the spelling of the workbook’s name in the sub-procedure and ensure it is correct. 

Cause #6: Specifying an Invalid Element

Sometimes when you use the shorthand form of a subscript, you may mistakenly specify an invalid element. 

For example, the shorthand for ActiveSheet.Range(“C3”) is [C3]. If this shorthand form of the subscript refers to an invalid element, you will get the “Subscript is out of range error.”

How to Fix It

Use a valid index or name for the collection. 

This tutorial has given reasons and solutions for the “Subscript out of range” error.  This error happens when we reference a non-existent collection member or a non-existent array element.

Examples of specific causes include 

  • Referencing a worksheet or workbook not present in the collection. 
  • Misspelling object names in the code.
  • Referencing a non-existent array element. 
  • Not specifying the number of elements in the array.
  • Attempting to access a closed workbook.
  • Specifying an invalid element. 

The solutions to the error include using the For Each…Next construct, instead of referencing specific items in the code and specifying the elements in an array. 

We hope you found the tutorial helpful.

Other articles you may also like:

  • Using Application.GetSaveAsFilename in VBA in Excel
  • Using Application.EnableEvents in VBA in Excel
  • SetFocus in Excel VBA – How to Use it?
  • How to Open Excel Files Using VBA
  • #NAME? Error in Excel – How to Fix!
  • #NUM! Error in Excel – How to Fix it?
  • SPILL Error in Excel – How to Fix?

Home > VBA > VBA Subscript Out of Range Runtime Error (Error 9)

Subscript Out of Range Error (Run Time: Error 9) occurs when you refer to an object or try to use a variable in a code that doesn’t exist in the code, in that case, VBA will show this error. As every code that you write is unique, so the cause of the error would be.

In the following example, you have tried to activate the “Sheet1” which is an object. But as you can see in the workbook no worksheet exists with the name “Sheet1” (instead you have “Sheet2”) so VBA show “Subscript Out of Range” to notify you that there’s something wrong with the code.

Subscript Out of Range

There could be one more situation when you have to face the error “Subscript Out of Range Error” when you are trying to declare a dynamic array but forget to use the DIM and ReDim statement to redefine the length of the array.

Now in the above code, you have an array with the name “myArray” and to make it dynamic we have initially left the array length blank. But before you add an item you need to redefine the array length using the ReDim statement.

And that’s the mistake we have made in the above code and VBA has returned the “Script Out of Range” error.

Sub myMacro()
Dim myArray() As Variant
myArray(1) = "One"
End Sub

How Do I Fix Subscript Out of Range in Excel?

The best way to deal with this Subscript Out of Range is to write effective codes and make sure to debug the code that you have written (Step by Step).

When you run a code step by step it is easy for you to know on which line of that code you have an error as VBA will show you the error message for Error 9 and highlight that line with yellow color.

The other thing that you can do is to use an “Error Handler” to jump to a specific line of error when it happens.

In the following code, we have written a line to activate the sheet but before that, we have used the goto statement to move to the error handler. In the error handler, you have a message box that shows you a message with the Err. Description that an error has occurred.

So, when you run this code and the “Sheet1” is not in the workbook where you are trying to activate it. It will show you a message box just like below.

And if the “Sheet1” is there then there won’t be any message at all.

Sub myMacro()

Dim wks As Worksheet

On Error GoTo myError
Sheets("Sheet1").Activate

myError:
MsgBox "There's an error in the code: " & Err.Description & _
". That means there's some problem with the sheet " & _
"that you want to activate"

End Sub

What is VBA

  • VBA ERROR Handling
  • VBA Automation Error (Error 440)
  • VBA Error 400
  • VBA Invalid Procedure Call Or Argument Error (Error 5)
  • VBA Object Doesn’t Support this Property or Method Error (Error 438)
  • VBA Object Required Error (Error 424)
  • VBA Out of Memory Error (Error 7)
  • VBA Overflow Error (Error 6)
  • VBA Runtime Error (Error 1004)
  • VBA Type Mismatch Error (Error 13)

VBA Subscript out of Range

Excel VBA Subscript out of Range

VBA Subscript out of Range or majorly knows as Run-Time Error 9 happens when we select such cell or sheet or workbook which actually does not come under range or criteria defined in Excel. It is like we have selected the range of 100 cells or a column and we have called out the values stored in 120 cells of the same column. Which means that we are going out of range to select and call out the values which are not in our defined criteria. When this kind of situation happens, we get a “Run-Time Error 9” message while compiling or running the code. VBA Subscript out of Range error message guides us to rectify the error which is related to the range we have selected in Excel.

Example of Excel VBA Subscript out of Range

Below are the different examples of VBA Subscript out of Range in Excel.

You can download this VBA Subscript out of Range Excel Template here – VBA Subscript out of Range Excel Template

VBA Subscript out of Range – Example #1

We will first consider a simple example. For this, we need to go to VBA windows and add a new module by going in Insert menu option as shown below.

VBA Subscript out of Range Example 1-1

We will get a white blank window of Module. This is where we need to do coding work.

Now write Subcategory of performed function, for best practice keep the name of a function in Subcategory, as we did here for VBA Subscript out of Range.

Code:

Sub Subscript_OutOfRange1()

End Sub

VBA Subscript out of Range Example 1-2

Here in excel, we have only one sheet named as “Sheet1” as shown below.

VBA Subscript out of Range Example 1-3

But we will write a code to select a sheet which is not even added and see what happens.

Now go to VBA window and write Sheets(2) followed by Select function as shown below. Which means, we are selecting Sheet sequence of 2nd position with Select function.

Code:

Sub Subscript_OutOfRange1()

  Sheets(2).Select

End Sub

VBA Subscript out of Range Example 1-4

Now compile the complete code or do it step by step to know which part of the code is an error. As we have only one line of code, we can directly run the code by clicking on the play button below the menu bar. We will get an error Message saying “Run-Time error 9, Subscript out of range” in the VBA as shown below.

Result of Example 1-5

This shows that we are trying to select that sheet which doesn’t exist. If we add a new sheet or change the sheet sequence in code from 2nd to 1st then we may get a successful code run. Let’s add another sheet and see what happens.

VBA Subscript out of Range Example 1-6

Now again run the code. And as we did not see any error, which means our code completes the successful run.

Result of Example 1-7

VBA Subscript out of Range – Example #2

In another example, we will see again a simple code of activating a Worksheet. For this again we will write the code. Start writing the Subcategory in the name of a performed function or in any other name as shown below.

Code:

Sub Subscript_OutOfRange2()

End Sub

VBA Subscript out of Range Example 2-1

Now with the help of Worksheet, we will activate Sheet1 as shown below.

Code:

Sub Subscript_OutOfRange2()

  Worksheets("Sheet1").Activate

End Sub

VBA Subscript out of Range Example 2-2

Now compile the complete code and run. We will notice there is no error message been popped-up which means code run is successful. Now let’s put the space in between “Sheet 1”

VBA Subscript out of Range Example 2-3

Again compile and run the code.

Result of Example 2-4

As we can see above, even if our complete process and way of writing the code are correct but we have taken in correct sheet name as “Sheet 1”. Which in reality has no space between “Sheet1”.

This shows, there are the still chances of getting an error if do not spell or write correct sheet name or workbook name.

VBA Subscript out of Range – Example #3

In this example, we will see how choosing incorrect Array range may create and show Run-time error 9. Start writing Subcategory again in the name of the performed function as shown below.

Code:

Sub Subscript_OutOfRange3()

End Sub

VBA Subscript out of Range Example 3-1

Now with the help of DIM define an Array of any size and gives it to String or Integers. Which depends, what we want to store in Array, numbers or text.

Here we have considered an array of 2×3 as String as shown below.

Code:

Sub Subscript_OutOfRange3()

  Dim SubArray(2, 3) As String

End Sub

VBA Subscript out of Range Example 3-2

By this, it will form a table for 2 rows and 3 columns and we can store any values as per our need. As we have selected String then we will consider text or alphabets in it.

Now in the second line of code, select the created array but with an extra or more column and assign a text as ABC or any other text as per your choice. Here, we have selected an Array of 2×5 as shown below.

Code:

Sub Subscript_OutOfRange3()

  Dim SubArray(2, 3) As String

  SubArray(2, 5) = ABC

End Sub

VBA Subscript out of Range Example 3-3

Now compile and run the code. As we can see in below screenshot, we got a VBA Subscript out of Range error message of Run-time error 9.

Result of Example 3-4

Reason for getting this error is because we have selected an incorrect Array range within 2 extra columns from 2×3 to 2×5, which is beyond the limit of code. Now if we again select the correct range of array as 2×3 and see what happens.

Result of Example 3-5

After compiling and running the code. We will see we did not receive any error which means our code run was successful.

Pros of Excel VBA Subscript out of Range

  • VBA Subscript out of Range allows us to know what kind of error has happened. So that we can specifically find the solution of the obtained error code.
  • As VBA subscript out of range ‘Run-time error 9’ is quite useful in knowing what kind of error has occurred in excel.

Things to Remember

  • It is recommended to use Subcategory in the name of the performed function with a sequence of code so that it would be easy to track it properly.
  • Save the file as Macro-Enabled Workbook to avoid losing written code.
  • If you have huge lines of code then it is better to compile each line of code one by one by pressing F8 key. This method compiles each step of code so that we can directly know which portion of code actually has the error in the first go.

Recommended Articles

This has been a guide to Excel VBA Subscript out of Range. Here we discussed why VBA Subscript out of Range error occurs (Run-time Error 9) along with some practical examples and downloadable excel template. You can also go through our other suggested articles –

  1. VBA IsError
  2. VBA Get Cell Value
  3. VBA On Error
  4. VBA XML

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