I’m trying an easy example using callback function, but it has some problem.
(function ddd () {
const categories = [];
const url2 = 'http://www.example.com';
const callback2 = function (res) {
console.log(res);
}
const callback = function (res,callback2) {
res.products.forEach((el) => {
categories.push({itemLabel: el.id, categoryLabel: 'gifts'});
});
callback2(categories);
};
getData(url2, callback);
})();
And console says callback2 is not a function
.
I tried console.log(typeof(callback2))
and it says callback2
is a function.
So, what is the problem in this situation? When I just type console.log(categories)
instead, it works well.
asked Feb 16, 2017 at 6:49
2
You have to do something like this.
getData(url2, callback(result, callback2));
answered Feb 16, 2017 at 6:56
kamprasadkamprasad
5983 silver badges12 bronze badges
2
You have to do something like this:
Important is to pass the second callback already in the first function as a argument.
If you don’t what to do this you can store the function in a global variable, but then it’s not really a callback.
(function ddd () {
const categories = [];
const url2 = 'http://www.example.com';
const callback2 = function (res) {
console.log(res);
}
const callback = function (res,callback2) {
res.products.forEach((el) => {
categories.push({itemLabel: el.id, categoryLabel: 'gifts'});
});
callback2(categories);
};
function getData(url, callback, callback2) {
callback({products: [{id: 10}]}, callback2);
};
getData(url2, callback, callback2);
})();
With Global Callback2:
(function ddd () {
const categories = [];
const url2 = 'http://www.example.com';
const callback2 = function (res) {
console.log(res);
}
const callback = function (res) {
res.products.forEach((el) => {
categories.push({itemLabel: el.id, categoryLabel: 'gifts'});
});
callback2(categories);
};
function getData(url, callback) {
callback({products: [{id: 10}]});
};
getData(url2, callback);
})();
answered Feb 16, 2017 at 6:59
patrickpatrick
8261 gold badge9 silver badges28 bronze badges
1
as i seen you are passing callback2 as a param to function callback, then not load the global definition he uses his own scope definition of callback.
const callback = function (res) {
res.products.forEach((el) => {
categories.push({itemLabel: el.id, categoryLabel: 'gifts'});
});
callback2(categories);
};
Removing callback2, from params method, will call callback2 defined previous , and dont find in own scope
answered Feb 16, 2017 at 6:51
Álvaro TouzónÁlvaro Touzón
1,2471 gold badge8 silver badges21 bronze badges
1
Are you trying to debug code and keep running into the aptly-named «TypeError: Callback is Not a Function» error? Fret not! This guide is here to help you understand why this error is appearing and how to fix it.
What is a TypeError?
A TypeError is a type of Error that appears in JavaScript console logs when a variable associated with the function is not of the expected data type. This can mean that you have either declared the variable with an incorrect type or the variable is not interacting correctly with the function.
Why does this error appear?
This particular error occurs because a variable is being passed as an argument to a function that expects a real callback function instead of the variable. When the variable is of a different type than the expected callback, a TypeError is thrown.
How to fix TypeError: Callback is Not a Function?
To resolve this issue, first inspect the code and identify the variable that is being passed to the function. Check the type of the variable and make sure it is a function that is compatible with the function expecting the callback.
If the expected function is expecting an Async
task, the callback must return a Promise with the value resolved.
If the variable is not compatible with the expected callback, you should define a new function that meets the compatibility requirements and use it as a callback.
FAQ
Q. What is a TypeError?
A. A TypeError is a type of Error that appears in JavaScript console logs when a variable associated with the function is not of the expected data type. This can mean that you have either declared the variable with an incorrect type or the variable is not interacting correctly with the function.
Q. Why does this error appear?
A. This particular error occurs because a variable is being passed as an argument to a function that expects a real callback function instead of the variable. When the variable is of a different type than the expected callback, a TypeError is thrown.
Q. What type of variable should be passed as a callback?
A. All variables passed as callbacks must be compatible with the expected function. If the expected function is expecting an Async
task, the callback must return a Promise with the value resolved.
Q. How to check the type of a variable?
A. JavaScript provides a typeof
operator to check the type of a variable. The typeof
operator returns the data type of the variable. For example, if the variable is a string, typeof
will return “String”.
Q. How to fix TypeError: Callback is Not a Function?
A. To resolve this issue, first inspect the code and identify the variable that is being passed to the function. Check the type of the variable and make sure it is a function that is compatible with the function expecting the callback. If the variable is not compatible with the expected callback, you should define a new function that meets the compatibility requirements and use it as a callback.
Resources:
- JavaScript & TypeError: Callback is Not a Function
- JavaScript typeof operator
- Learn All About JavaScript Callback Functions
The “typeerror: callback is not a function” is an error message that occurs in JavaScript.
This article will help you learn, understand, and fix this error.
Remember that it is crucial to understand the error first before proceeding to the steps to fix it.
So, without further ado, let us start with understanding this error.
As mentioned in our first sentence, typeerror: callback is not a function is an error message that occurs in JavaScript.
This error occurs when a function’s callback argument is given, but the function is called without passing the callback as a parameter.
Here is a sample code that causes this error:
function sample(callback) {
return callback();
}
sample();
Error:
index.js:2
return callback();
^
TypeError: callback is not a function
To fix this error, follow the guide below.
Typeerror: callback is not a function – SOLUTION
Fixing the typeerror: callback is not a function may sound frustrating, but it is easy and quick.
See the sample code below to help you fix the error you are facing.
Sample code:
function sample(callback = () => {}){
return callback();
}
sample();
Aside from the sample code above, you can also fix it using this code:
function sample(callback) {
return callback();
}
sample(() => {
console.log('This is a success!');
});
Output:
This is a success!
If you only want to test a code, use our online JavaScript compiler. In there, you can run JS code online for free.
FAQs
🗨 Is a callback function a function?
The answer is yes.
A callback() function is a function in JavaScript.
It is a function that is passed to another function as an argument.
It is then invoked from within the external function to complete a task.
🗨 How to add a callback function in JavaScript?
To add a callback function in JavaScript, first you have to pass it to another function as a parameter.
Then, after the task is finished, call it back.
🗨 What is TypeError?
Typeerror is an error in Python that arises when an operation or function is applied to a value of an improper type.
This error indicates that the data type of an object isn’t compatible with the operation or function being used.
🗨 What is Python?
Python is one of the most popular programming languages.
It is used for developing a wide range of applications.
In addition, Python is a high-level programming language that is used by most developers due to its flexibility.
Conclusion
In conclusion, the typeerror: callback is not a function occurs in JavaScript as an error message.
You can solve this error by using the arrow function to define the callback() function, then returning it to the callback() function.
By following the guide above, you will surely solve this error quickly.
That is all for this tutorial, IT source coders!
We hope you have learned a lot from this. Have fun coding!
Thank you for reading! 😊
Comments
This was referenced
Aug 20, 2019
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Oct 25, 2019
It seems that we have a dep to an old version of scheduler that doesn't work very well with React Hook see this issue: facebook/react#15647
Crash—
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Oct 28, 2019
It seems that we have a dep to an old version of scheduler that doesn't work very well with React Hook see this issue: facebook/react#15647
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Answer by Hadleigh Parker
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Where developers & technologists share private knowledge with coworkers
i.e. Instead of…
const [result] = await mySoapClient.Perform_Operation({ ... })
I needed to append the word Async
to the method. e.g.
const [result] = await mySoapClient.Perform_OperationAsync({ ... })
Answer by Heath Xiong
I’ll get around to trying method calls and seeing if that works some other time. Bit tired with this issue.,This error can be reproduced (I think) if the server is closed and then opened again quickly. Which makes me think it has something to do with the twitter server. Also sometimes this error is being returned kind of randomly. Maybe it has to do with the timeout function / reconnect logic?:,Not entirely sure how to get around this, might have to do something with uncaughtException.
/var/www/html/01014.org/public_html/srv/node_modules/needle/lib/needle.js:468
return callback(err, resp, resp ? resp.body : undefined);
^
TypeError: callback is not a function
at done (/var/www/html/01014.org/public_html/srv/node_modules/needle/lib/needle.js:468:14)
at PassThrough.<anonymous> (/var/www/html/01014.org/public_html/srv/node_modules/needle/lib/needle.js:719:9)
at PassThrough.emit (events.js:315:20)
at endReadableNT (_stream_readable.js:1220:12)
at processTicksAndRejections (internal/process/task_queues.js:84:21)
Answer by Ronan Benitez
I have plenty more content planned for the future, so if you found this helpful and want to receive it directly to your inbox without having to remember to check back here, sign up below:,But what if we wanted to convert a callback function directly to an async/await version of that function? Without using Promises directly?,If we don’t pass in a callback, we get a TypeError: callback is not a function error.
const callbackFn = (firstName, callback) => {
setTimeout(() => {
if (!firstName) return callback(new Error('no first name passed in!'))
const fullName = `${firstName} Doe`
return callback(fullName)
}, 2000)
}
callbackFn('John', console.log)
callbackFn(null, console.log)
And here’s the Promise-based version of that function:
const promiseFn = firstName => {
return new Promise((resolve, reject) => {
setTimeout(() => {
if (!firstName) reject(new Error('no first name passed in!'))
const fullName = `${firstName} Doe`
resolve(fullName)
}, 2000)
})
}
promiseFn('Jane').then(console.log)
promiseFn().catch(console.log)
The great thing about having our function in Promise form is that we don’t actually need to «make it an async/await version» if we don’t want to. When we call/execute the function, we can simply use the async/await
keyword, like so:
const result = (async () => {
try {
console.log(await promiseFn('Jim'))
} catch (e) {
console.log(e)
}
try {
console.log(await promiseFn())
} catch (e) {
console.log(e)
}
})()
async/await
is syntactic sugar around Promises, so it uses them under the hood. Here’s how you can convert it:
const timeout = ms => {
return new Promise(resolve => setTimeout(resolve, ms))
}
const asyncAwaitFn = async firstName => {
await timeout(2000) // using timeout like this makes it easier to demonstrate callback -> async/await conversion
if (!firstName) throw new Error('no first name passed in!')
const fullName = `${firstName} Doe`
return fullName
}
const res = (async () => {
try {
console.log(await asyncAwaitFn('Jack'))
} catch (e) {
console.log(e)
}
try {
console.log(await asyncAwaitFn())
} catch (e) {
console.log(e)
}
})()